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Explain the mechanism of solidification of an alloy at 72 wt% Ag

Question

Explain the mechanism of solidification of an alloy at 72 wt% Ag

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Solution

The solidification of an alloy at 72 wt% Ag (Silver) involves a process known as binary isomorphous solidification. Here's a step-by-step explanation:

  1. Melting Point: The process begins when the alloy is heated to a temperature above the melting point of both Ag and the other metal in the alloy. At this temperature, both metals are in a liquid state.

  2. Cooling: The alloy is then slowly cooled. As the temperature drops, the metals begin to solidify. However, because the alloy is 72 wt% Ag, the silver will begin to solidify first.

  3. Solidification of Silver: As the temperature continues to drop, more and more silver atoms will find their places in the crystal lattice and solidify. This is because silver has a higher concentration in the alloy and thus a higher probability of forming bonds with other silver atoms.

  4. Solidification of the Other Metal: Once the temperature drops to the melting point of the other metal in the alloy, it will also begin to solidify. However, because it is less concentrated in the alloy, it will solidify at a slower rate than the silver.

  5. Formation of the Solid Solution: As both metals solidify, they will form a solid solution. This is a homogeneous mixture of the two metals in which the atoms of one metal replace some of the atoms in the crystal lattice of the other metal.

  6. Final Solidification: The alloy is completely solidified when the temperature drops below the melting point of the other metal. At this point, the alloy is a solid solution of 72 wt% Ag and the remaining percentage of the other metal.

This process results in a uniform distribution of the two metals throughout the solid alloy, which can enhance the alloy's properties such as strength, corrosion resistance, and ductility.

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