Which of the following explains the resulting image of an object located exactly at the center of curvature of a concave mirror?Group of answer choicessame size, inverted, at C and reallarger, upright, at C, and realsmaller, inverted, at C, and invertedsame size, upright, at C, and real
Question
Which of the following explains the resulting image of an object located exactly at the center of curvature of a concave mirror?Group of answer choicessame size, inverted, at C and reallarger, upright, at C, and realsmaller, inverted, at C, and invertedsame size, upright, at C, and real
Solution
The correct answer is "same size, inverted, at C and real".
Here's why:
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When an object is placed at the center of curvature (C) of a concave mirror, the image is formed at the same location (C).
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The image is of the same size as the object. This is because the rays of light coming from the object are reflected back along the same path.
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The image is inverted, meaning it is upside down. This is a characteristic of images formed by concave mirrors when the object is placed beyond the focal point.
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The image is real, which means it can be projected on a screen. Real images are formed when the reflected rays of light actually meet.
So, the image of an object located exactly at the center of curvature of a concave mirror is the same size, inverted, at C, and real.
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