Which of the following is a valid declaration of a char?char ch = '\utea';char ca = 'tea';char cr = \u0223;char cc = '\itea';
Question
Which of the following is a valid declaration of a char?char ch = '\utea';char ca = 'tea';char cr = \u0223;char cc = '\itea';
Solution
The valid declaration of a char is: char cr = '\u0223';
Explanation:
-
char ch = '\utea'; - This is not valid because '\utea' is not a valid unicode escape sequence. Unicode escape sequences consist of '\u' followed by exactly 4 hexadecimal digits.
-
char ca = 'tea'; - This is not valid because 'tea' is more than one character. A char can only hold a single character.
-
char cr = '\u0223'; - This is valid. '\u0223' is a valid unicode escape sequence.
-
char cc = '\itea'; - This is not valid because '\itea' is not a recognized escape sequence or unicode escape sequence.
Similar Questions
Identify correct syntaxIdentify the correct syntax to use char data typeSelect one of the following options:character ch = 'c';char ch = 'ch';char ch 'ch'None of the above
Which of the following declaration is not supported by C language?String str;Both “String str;” and “float str = 3e2;”float str = 3e2;char *str;Clear my choice
Which of the following would declare a character variable, named letter, which consists of a single letter?a.)char letter = 'a';b.)String letter = 'a';c.)char letter ="a";d.)String letter = "a";
Identify correct syntaxIdentify the correct syntax to use char data type
Which of the following is an invalid identifier in C?
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.