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2x + (3y - 6) i= 4 + 12i find the value of x and y

Question

2x + (3y - 6) i= 4 + 12i find the value of x and y

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Solution

The given equation is a complex equation, which means it has both real and imaginary parts. We can equate the real parts and the imaginary parts separately.

The given equation is: 2x + (3y - 6)i = 4 + 12i

Equating the real parts: 2x = 4 => x = 4/2 => x = 2

Equating the imaginary parts: 3y - 6 = 12 => 3y = 12 + 6 => 3y = 18 => y = 18/3 => y = 6

So, the solution to the equation is x = 2 and y = 6.

This problem has been solved

Similar Questions

x + 3y = 6 ; 2x – 3y = 12

For the equation 3x – 2y = 12, which has value of −6?

x2-4x+y2+6y=12

2x + y = 6,   -2x + 3y = 5

6y 2 −3y−4=y 2

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