wo balls having volumes as 100 cm^3 and 150 cm^3 are immersed completely in a liquid at a depth of 3 m and 2 m respectively the ratio of buoyancy acting on them is?

To find the ratio of buoyancy acting on the two balls, we need to consider the principle of Archimedes' buoyancy.

The buoyant force acting on an object submerged in a fluid is equal to the weight of the fluid displaced by the object. This can be calculated using the formula:

Buoyant force = density of fluid * volume of fluid displaced * acceleration due to gravity

In this case, both balls are completely immersed in the same liquid, so the density of the fluid and the acceleration due to gravity are constant.

Let's calculate the buoyant force for each ball:

For the first ball with a volume of 100 cm^3, the buoyant force can be calculated as:

Buoyant force 1 = density of fluid * volume of fluid displaced by ball 1 * acceleration due to gravity

For the second ball with a volume of 150 cm^3, the buoyant force can be calculated as:

Buoyant force 2 = density of fluid * volume of fluid displaced by ball 2 * acceleration due to gravity

Since both balls are immersed at different depths, the volume of fluid displaced by each ball will be different. To calculate the volume of fluid displaced, we need to consider the height of immersion.

For the first ball immersed at a depth of 3 m, the volume of fluid displaced can be calculated as:

Volume of fluid displaced by ball 1 = cross-sectional area of ball 1 * height of immersion

Similarly, for the second ball immersed at a depth of 2 m, the volume of fluid displaced can be calculated as:

Volume of fluid displaced by ball 2 = cross-sectional area of ball 2 * height of immersion

Now, we can calculate the ratio of buoyancy acting on the two balls:

Ratio of buoyancy = Buoyant force 1 / Buoyant force 2

By substituting the calculated values, we can find the desired ratio.