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A train starting from station X was to arrive at station Y at 6:06 PM. It could travel at 62.5% of its usual speed and reach Y at 7 PM. At what time did it start from X?

Question

A train starting from station X was to arrive at station Y at 6:06 PM. It could travel at 62.5% of its usual speed and reach Y at 7 PM. At what time did it start from X?

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Solution

To solve this problem, we first need to determine the time difference between the expected arrival time and the actual arrival time.

  1. The train was expected to arrive at 6:06 PM but actually arrived at 7 PM. So, the delay is 54 minutes (from 6:06 PM to 7 PM).

  2. This delay was caused by the train traveling at 62.5% of its usual speed. This means it was traveling slower than usual.

  3. If 100% represents the usual speed, then the time taken when the train travels at 62.5% of its speed is 100/62.5 = 1.6 times the usual time.

  4. Therefore, the usual time taken by the train (without the delay) would be 54 minutes / 1.6 = 33.75 minutes.

  5. So, the train started from station X at 6:06 PM - 33.75 minutes = 5:32 PM (approximately).

Therefore, the train started from station X at around 5:32 PM.

This problem has been solved

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