What will be the output of the following code snippet for the list 1->2->3->4->5->6?def fun(start): if start is None: return print(start.data, end=" ") if start.next is not None: fun(start.next.next) print(start.data, end=" ")Options1 2 3 4 5 61 3 5 5 3 11 3 5 1 3 52 4 6 1 3 5

The output of the given code snippet will be "1 3 5 5 3 1".

Here's the step by step explanation:

1. The function fun() is a recursive function that prints the data of the current node, skips one node, and then calls itself again with the next node.

2. The function starts with the first node of the list (1). It prints the data of the current node (1), skips the next node (2), and calls itself with the next node (3).

3. The function now has the third node (3). It prints the data of the current node (3), skips the next node (4), and calls itself with the next node (5).

4. The function now has the fifth node (5). It prints the data of the current node (5), but there is no next node to skip, so it doesn't call itself again.

5. The function then returns to the previous call (with the third node), and prints the data of the current node again (3).

6. The function then returns to the first call (with the first node), and prints the data of the current node again (1).

So, the output of the function for the list 1->2->3->4->5->6 will be "1 3 5 5 3 1".