If 2 cards are selected from a standard deck of cards. The first card is placed backin the deck before the second card is drawn. Find the probability of getting:A red card and 4 of spades (in exact order)
Question
If 2 cards are selected from a standard deck of cards. The first card is placed backin the deck before the second card is drawn. Find the probability of getting:A red card and 4 of spades (in exact order)
Solution
Sure, here is the step by step solution:
Step 1: Understand the problem We are drawing 2 cards from a standard deck of 52 cards. The first card drawn is placed back in the deck before the second card is drawn. We need to find the probability of drawing a red card first and then the 4 of spades.
Step 2: Calculate the probability of drawing a red card A standard deck has 26 red cards (13 hearts and 13 diamonds). So, the probability of drawing a red card is 26/52 = 1/2.
Step 3: Calculate the probability of drawing the 4 of spades Since the first card is placed back in the deck, we still have 52 cards in the deck when we draw the second card. There is only one 4 of spades in the deck, so the probability of drawing the 4 of spades is 1/52.
Step 4: Calculate the overall probability Since these are independent events (the outcome of the first draw does not affect the outcome of the second draw), we can find the overall probability by multiplying the probabilities of the individual events. So, the overall probability is (1/2) * (1/52) = 1/104.
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