For an enzyme in the absence of inhibitor Vmax is 10 μM.s-1 and its Km is 2 mM. In the presence of a 3 mM inhibitor the apparent Vmax is 6.67 μM.s-1 and the apparent Km is 4 mM.Select the correct statementGroup of answer choicesalpha and alpha' = 3alpha' = 3alpha' = 2alpha = 1.5 and alpha' = 3alpha = 1.5alpha = 3 and alpha' = 1.5

The correct statement is: "alpha = 1.5 and alpha' = 3"

Explanation: In enzyme kinetics, alpha (α) and alpha prime (α') are used to describe the effects of inhibitors on the maximum rate of reaction (Vmax) and the

The alpha (α) and alpha prime (α') values are used to determine the type of inhibition an enzyme is experiencing.

α is the ratio of the apparent Km in the presence of inhibitor to the Km in the absence of inhibitor (Km(app)/Km).

α' is the ratio of the apparent Vmax in the absence of inhibitor to the Vmax in the presence of inhibitor (Vmax/Vmax(app)).

Given the values in the question:

α = Km(app)/Km = 4 mM / 2 mM = 2

α' = Vmax/Vmax(app) = 10 μM.s-1 / 6.67 μM.s-1 = 1.5

So, the correct statement is "alpha = 2 and alpha' = 1.5". However, this option is not given in your list of answer choices.

If we consider the closest match from the given options, then "alpha = 1.5 and alpha' = 3" would be the closest, but it's not the accurate calculation based on the given data.