A filter consist of resistance = 25k Ohm. and capacitance = 220 pF. Find out the cut of frequency.28.937 KHz2.8937 MHz28.937 Hz2.8937 KHz
Question
A filter consist of resistance = 25k Ohm. and capacitance = 220 pF. Find out the cut of frequency.28.937 KHz2.8937 MHz28.937 Hz2.8937 KHz
Solution
The cut-off frequency for a RC (resistor-capacitor) filter can be calculated using the formula:
f_c = 1 / (2πRC)
where: f_c is the cut-off frequency, R is the resistance (in ohms), C is the capacitance (in farads), and π is a constant (approximately 3.14159).
Given that R = 25k Ohm = 25000 Ohm and C = 220 pF = 220 x 10^-12 Farads, we can substitute these values into the formula:
f_c = 1 / (2π * 25000 * 220 x 10^-12)
Solving this equation gives:
f_c = 28.937 KHz
So, the cut-off frequency of the filter is 28.937 KHz.
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