What will be the output of the following Java program?class control_statements { public static void main(String args[]) { int sum = 0; for (int u = 5, v = 5; u < 10 & v < 10; ++u, v = u + 1) sum += u; System.out.println(sum); } }Options261015compilation error
Question
What will be the output of the following Java program?class control_statements { public static void main(String args[]) { int sum = 0; for (int u = 5, v = 5; u < 10 & v < 10; ++u, v = u + 1) sum += u; System.out.println(sum); } }Options261015compilation error
Solution
The output of the given Java program will be 26.
Here's the step by step explanation:
-
The program starts with the declaration of an integer variable
sumand initializes it to 0. -
Then, a
forloop is started with two variablesuandv, both initialized to 5. -
The loop condition is
u < 10 & v < 10. The&operator is a bitwise AND operator, which returns true if both conditions are true. So, the loop will continue as long as bothuandvare less than 10. -
Inside the loop, the value of
uis added tosum(sum += u;), and thenuis incremented by 1 (++u). After that,vis set tou + 1. -
The loop will run for
u= 5, 6, 7, 8, 9. Whenubecomes 10, the loop conditionu < 10 & v < 10will be false, and the loop will stop. -
The values of
uadded tosumduring the loop are 5, 6, 7, 8, 9. The sum of these numbers is 35. -
Finally, the program prints the value of
sum, which is 35.
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