The output period of a frequency division circuit that contains 2 flip-flops with an input clock frequency of 50 MHz is:
Question
The output period of a frequency division circuit that contains 2 flip-flops with an input clock frequency of 50 MHz is:
Solution
The output period of a frequency division circuit can be calculated using the formula:
Tout = 2^n * Tin
where:
- Tout is the output period
- n is the number of flip-flops
- Tin is the input period
First, we need to find the input period (Tin) which is the reciprocal of the input frequency. The input frequency is given as 50 MHz, so:
Tin = 1 / 50 MHz = 20 ns
Next, we calculate the output period using the formula. The number of flip-flops (n) is given as 2, so:
Tout = 2^2 * 20 ns = 4 * 20 ns = 80 ns
So, the output period of a frequency division circuit that contains 2 flip-flops with an input clock frequency of 50 MHz is 80 ns.
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