Question 10Complete the Frequency × midpoint column.ClassintervalFrequency(f)Midpoint(x)Frequency ×midpoint(fx)0 < x 10 8 510 < x2010 15 15020 < x3012 25 30030 < x4014 35 49040 < x506 45 270
Question
Question 10Complete the Frequency × midpoint column.ClassintervalFrequency(f)Midpoint(x)Frequency ×midpoint(fx)0 < x 10 8 510 < x2010 15 15020 < x3012 25 30030 < x4014 35 49040 < x506 45 270
Solution
The Frequency × midpoint column is completed by multiplying the values in the Frequency (f) column with the corresponding values in the Midpoint (x) column. Here's how it's done:
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For the first row, the frequency is 8 and the midpoint is 5. Multiply these together to get 40. So, the value for the first row in the Frequency × midpoint column is 40.
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For the second row, the frequency is 10 and the midpoint is 15. Multiply these together to get 150. So, the value for the second row in the Frequency × midpoint column is 150.
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For the third row, the frequency is 12 and the midpoint is 25. Multiply these together to get 300. So, the value for the third row in the Frequency × midpoint column is 300.
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For the fourth row, the frequency is 14 and the midpoint is 35. Multiply these together to get 490. So, the value for the fourth row in the Frequency × midpoint column is 490.
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For the fifth row, the frequency is 6 and the midpoint is 45. Multiply these together to get 270. So, the value for the fifth row in the Frequency × midpoint column is 270.
So, the completed Frequency × midpoint column is: 40, 150, 300, 490, 270.
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