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If 4 cot ๐œƒ โˆ’ 5 = 0, then the value of 5 sin ๐œƒโˆ’4 cos ๐œƒ5 sin ๐œƒ+4 cos ๐œƒ is

Question

If 4 cot ๐œƒ โˆ’ 5 = 0, then the value of 5 sin ๐œƒโˆ’4 cos ๐œƒ5 sin ๐œƒ+4 cos ๐œƒ is

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Solution

To find the value of 5 sin ๐œƒโˆ’4 cos ๐œƒ / 5 sin ๐œƒ+4 cos ๐œƒ, we need to first solve the equation 4 cot ๐œƒ โˆ’ 5 = 0.

Step 1: Rearrange the equation to isolate cot ๐œƒ: 4 cot ๐œƒ = 5

Step 2: Divide both sides of the equation by 4: cot ๐œƒ = 5/4

Step 3: Take the reciprocal of both sides to find the value of tan ๐œƒ: tan ๐œƒ = 4/5

Step 4: Use the Pythagorean identity to find the value of sin ๐œƒ and cos ๐œƒ: sin ๐œƒ = โˆš(1 - cos^2 ๐œƒ) cos ๐œƒ = โˆš(1 - sin^2 ๐œƒ)

Step 5: Substitute the values of sin ๐œƒ and cos ๐œƒ into the expression 5 sin ๐œƒโˆ’4 cos ๐œƒ / 5 sin ๐œƒ+4 cos ๐œƒ: 5(โˆš(1 - sin^2 ๐œƒ)) - 4(โˆš(1 - cos^2 ๐œƒ)) / 5(โˆš(1 - sin^2 ๐œƒ)) + 4(โˆš(1 - cos^2 ๐œƒ))

Step 6: Simplify the expression further if possible.

Please note that the specific values of sin ๐œƒ and cos ๐œƒ cannot be determined without additional information.

This problem has been solved

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