A line passes through the point 4, 6 and has a slope of 5.Write an equation in slope-intercept form for this line.
Question
A line passes through the point 4, 6 and has a slope of 5.Write an equation in slope-intercept form for this line.
Solution
To find the equation of a line in slope-intercept form, we need to use the point-slope form of a line and then rearrange the equation to isolate y.
The point-slope form of a line is given by: y - y1 = m(x - x1)
where (x1, y1) is a point on the line and m is the slope.
In this case, the given point is (4, 6) and the slope is 5. Plugging these values into the point-slope form, we have: y - 6 = 5(x - 4)
Now, let's simplify the equation: y - 6 = 5x - 20
To isolate y, we can add 6 to both sides of the equation: y = 5x - 20 + 6
Simplifying further: y = 5x - 14
Therefore, the equation of the line in slope-intercept form is y = 5x - 14.
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