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A line passes through the point 4, 6 and has a slope of 5.Write an equation in slope-intercept form for this line.

Question

A line passes through the point 4, 6 and has a slope of 5.Write an equation in slope-intercept form for this line.

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Solution

To find the equation of a line in slope-intercept form, we need to use the point-slope form of a line and then rearrange the equation to isolate y.

The point-slope form of a line is given by: y - y1 = m(x - x1)

where (x1, y1) is a point on the line and m is the slope.

In this case, the given point is (4, 6) and the slope is 5. Plugging these values into the point-slope form, we have: y - 6 = 5(x - 4)

Now, let's simplify the equation: y - 6 = 5x - 20

To isolate y, we can add 6 to both sides of the equation: y = 5x - 20 + 6

Simplifying further: y = 5x - 14

Therefore, the equation of the line in slope-intercept form is y = 5x - 14.

This problem has been solved

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