A sample of air from an industrial plant was tested and found to contain 49.33 mircograms/m3 of soot particles. What mass (in ng) would be inhaled in each 0.500 L breath?Give your answer correct to three significant figures.Group of answer choices24.7 ng0.0298 ng32.5 x 106 ng1.21 ng
Question
A sample of air from an industrial plant was tested and found to contain 49.33 mircograms/m3 of soot particles. What mass (in ng) would be inhaled in each 0.500 L breath?Give your answer correct to three significant figures.Group of answer choices24.7 ng0.0298 ng32.5 x 106 ng1.21 ng
Solution
First, we need to convert the volume of each breath from liters to cubic meters, since the concentration of soot particles is given in micrograms per cubic meter.
1 cubic meter (m^3) is equal to 1000 liters (L), so 0.500 L is equal to 0.0005 m^3.
Next, we multiply the concentration of soot particles by the volume of each breath to find the mass of soot particles inhaled in each breath:
49.33 micrograms/m^3 * 0.0005 m^3 = 0.024665 micrograms
Since 1 microgram is equal to 1000 nanograms (ng), we convert the mass of soot particles from micrograms to nanograms:
0.024665 micrograms * 1000 = 24.665 ng
Rounding to three significant figures, the mass of soot particles inhaled in each 0.500 L breath is 24.7 ng.
So, the correct answer is 24.7 ng.
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