What would be the product after treating acetaldehyde with K2Cr2O7 in H2SO4?Question 6Answera.Ethanoic acidb.Acetonec.Acetald.Ethanol
Question
What would be the product after treating acetaldehyde with K2Cr2O7 in H2SO4?Question 6Answera.Ethanoic acidb.Acetonec.Acetald.Ethanol
Solution
The product of treating acetaldehyde (CH3CHO) with potassium dichromate (K2Cr2O7) in sulfuric acid (H2SO4) would be ethanoic acid (CH3COOH).
Here's the step-by-step process:
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Potassium dichromate (K2Cr2O7) in sulfuric acid (H2SO4) is a strong oxidizing agent.
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When acetaldehyde (CH3CHO) is treated with this oxidizing agent, the aldehyde group (-CHO) gets oxidized to a carboxylic acid group (-COOH).
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Therefore, acetaldehyde (CH3CHO) gets converted to ethanoic acid (CH3COOH).
So, the correct answer is a. Ethanoic acid.
Similar Questions
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