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Write the empirical formula of at least four binary ionic compounds that could be formed from the following ions:Fe2+, Pb4+, Cl−, S2−

Question

Write the empirical formula of at least four binary ionic compounds that could be formed from the following ions:Fe2+, Pb4+, Cl−, S2−

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Solution

  1. Iron (II) Chloride: The iron (II) ion has a charge of +2 and the chloride ion has a charge of -1. To balance the charges, we need two chloride ions for each iron (II) ion. So, the empirical formula is FeCl2.

  2. Iron (II) Sulfide: The iron (II) ion has a charge of +2 and the sulfide ion has a charge of -2. The charges are already balanced, so we need one of each ion. The empirical formula is FeS.

  3. Lead (IV) Chloride: The lead (IV) ion has a charge of +4 and the chloride ion has a charge of -1. To balance the charges, we need four chloride ions for each lead (IV) ion. So, the empirical formula is PbCl4.

  4. Lead (IV) Sulfide: The lead (IV) ion has a charge of +4 and the sulfide ion has a charge of -2. To balance the charges, we need two sulfide ions for each lead (IV) ion. So, the empirical formula is PbS2.

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Fill in the name and empirical formula of each ionic compound that could be formed from the ions in this table:Some ionic compoundscation anion empirical formula name of compoundSn4+ Cl− Sn2+ Cl− Na+ Cl− Mg2+ Cl−

To fill in the table, we need to balance the charges of the cations and anions to find the empirical formula for each ionic compound. Then we can name the compound accordingly. 1. For the cation Fe^3+ and the anion S^2-: - To balance the charges, we need two Fe^3+ ions for every three S^2- ions. - The empirical formula is Fe2S3. - The name of the compound is iron(III) sulfide. 2. For the cation Pb^4+ and the anion O^2-: - To balance the charges, we need two Pb^4+ ions for every four O^2- ions (which simplifies to one Pb^4+ for every two O^2-). - The empirical formula is PbO2. - The name of the compound is lead(IV) oxide. 3. For the cation Mn^2+ and the anion N^3-: - To balance the charges, we need three Mn^2+ ions for every two N^3- ions. - The empirical formula is Mn3N2. - The name of the compound is manganese(II) nitride. 4. For the cation Fe^2+ and the anion P^3-: - To balance the charges, we need three Fe^2+ ions for every two P^3- ions. - The empirical formula is Fe3P2. - The name of the compound is iron(II) phosphide. So the completed table should list the empirical formulas and names of the compounds as follows: - Fe2S3, iron(III) sulfide- PbO2, lead(IV) oxide- Mn3N2, manganese(II) nitride- Fe3P2, iron(II) phosphide

Some ionic compoundscation anion empirical formula name of compoundPb4+ Cl− Pb2+ Cl− Cs+ Cl− Ba2+ Cl−

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