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We can imagine the xylem formed by ducts of 0.02 mm radius that in their upper part are closed by the leaves, which have pores of 5 nm radius. Determine: (a) the flow rate through a conduit in a tree 30 m high, if the pressure at the top is ten percent greater than that necessary to maintain the water column, (b) the pressure necessary to maintain the same flow rate in a set of vessels with a radius of 5 nm and whose total area was equal to that of the xylem vessel.

Question

We can imagine the xylem formed by ducts of 0.02 mm radius that in their upper part are closed by the leaves, which have pores of 5 nm radius. Determine: (a) the flow rate through a conduit in a tree 30 m high, if the pressure at the top is ten percent greater than that necessary to maintain the water column, (b) the pressure necessary to maintain the same flow rate in a set of vessels with a radius of 5 nm and whose total area was equal to that of the xylem vessel.

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Solution

To solve this problem, we need to use the Poiseuille's law, which states that the flow rate (Q) through a cylindrical pipe is directly proportional to the fourth power of the radius (r), the pressure difference (ΔP), and inversely proportional to the length (L) and the viscosity (η) of the fluid. The equation is:

Q = (πr⁴ΔP) / (8ηL)

(a) To find the flow rate through a conduit in a tree 30 m high, we need to know the pressure difference (ΔP). The problem states that the pressure at the top is ten percent greater than that necessary to maintain the water column. The pressure necessary to maintain a water column of height h is given by ρgh, where ρ is the density of water (1000 kg/m³), g is the acceleration due to gravity (9.81 m/s²), and h is the height of the water column (30 m). So, ΔP = 1.1ρgh - ρgh = 0.1ρgh = 0.1 * 1000 kg/m³ * 9.81 m/s² * 30 m = 29430 Pa. The viscosity of water (η) is approximately 1.002 x 10^-3 Pa.s. Substituting these values into the Poiseuille's law, we get:

Q = (π * (0.02 m)⁴ * 29430 Pa) / (8 * 1.002 x 10^-3 Pa.s * 30 m) = 0.000000145 m³/s

(b) To find the pressure necessary to maintain the same flow rate in a set of vessels with a radius of 5 nm, we need to rearrange the Poiseuille's law to solve for ΔP:

ΔP = (8ηLQ) / (πr⁴)

The total area of the set of vessels is equal to that of the xylem vessel, so the number of vessels is (0.02 m / 5 x 10^-9 m)² = 1.6 x 10^16. Since the flow rate is divided equally among all vessels, the flow rate through each vessel is 0.000000145 m³/s / 1.6 x 10^16 = 9.0625 x 10^-24 m³/s. Substituting these values into the rearranged Poiseuille's law, we get:

ΔP = (8 * 1.002 x 10^-3 Pa.s * 30 m * 9.0625 x 10^-24 m³/s) / (π * (5 x 10^-9 m)⁴) = 1.38 x 10^9 Pa.

This problem has been solved

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