A 2 Kg box is put on the surface of an inclined plane at 27 ° with the horizontal. The surface of the inclined plane is assumed to be frictionless.Draw a free body diagram of the box on the inclined plane and label all forces acting on the box.
Question
A 2 Kg box is put on the surface of an inclined plane at 27 ° with the horizontal. The surface of the inclined plane is assumed to be frictionless.Draw a free body diagram of the box on the inclined plane and label all forces acting on the box.
Solution
Step 1: Draw a rectangle to represent the box.
Step 2: Draw a line from the center of the box downwards. This line represents the force of gravity (Fg) acting on the box. Label this line as "Fg = 2kg * 9.8m/s^2" (since the force of gravity is mass times the acceleration due to gravity).
Step 3: Draw a line from the center of the box perpendicular to the inclined plane. This line represents the normal force (Fn) acting on the box. Label this line as "Fn".
Step 4: Draw a line from the center of the box along the inclined plane downwards. This line represents the force due to gravity along the plane (Fgp). Label this line as "Fgp = Fg * sin(27°)" (since the force of gravity along the plane is the force of gravity times the sine of the angle of the plane).
Step 5: Since there is no friction, there are no other forces acting on the box.
So, the free body diagram of the box on the inclined plane includes the force of gravity (Fg), the normal force (Fn), and the force due to gravity along the plane (Fgp).
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