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Alice spent 30% of her money on a blouse and 40% of the remaining money on a skirt. She spent $56 on the skirt. How much money did she have at first?

Question

Alice spent 30% of her money on a blouse and 40% of the remaining money on a skirt. She spent $56 on the skirt. How much money did she have at first?

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Solution

Sure, let's solve this step by step:

  1. First, we know that Alice spent 40% of her remaining money on a skirt, which cost 56.So,wecansetuptheequation0.40X=56. So, we can set up the equation 0.40 * X = 56, where X is the amount of money Alice had after buying the blouse. Solving for X gives us X = 56/0.40=56 / 0.40 = 140.

  2. Next, we know that the 140is70140 is 70% of the total amount of money Alice had at first (since she spent 30% on a blouse and had 70% left). So, we can set up the equation 0.70 * Y = 140, where Y is the total amount of money Alice had at first. Solving for Y gives us Y = 140/0.70=140 / 0.70 = 200.

So, Alice had $200 at first.

This problem has been solved

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