Eddie is in a hot air balloon that has just taken off and is now floating 7 metres above its launching point. Camille is standing on the ground, 7 metres away from the launching point. How far apart are Eddie and Camille? If necessary, round to the nearest tenth.
Question
Eddie is in a hot air balloon that has just taken off and is now floating 7 metres above its launching point. Camille is standing on the ground, 7 metres away from the launching point. How far apart are Eddie and Camille? If necessary, round to the nearest tenth.
Solution
To solve this problem, we can use the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.
Here, we can imagine a right triangle where one side is the vertical distance from Eddie to the ground (7 metres), the other side is the horizontal distance from Camille to the launching point (also 7 metres), and the hypotenuse is the straight-line distance between Eddie and Camille, which we're trying to find.
According to the Pythagorean theorem:
(distance between Eddie and Camille)^2 = (vertical distance)^2 + (horizontal distance)^2 (distance between Eddie and Camille)^2 = (7 metres)^2 + (7 metres)^2 (distance between Eddie and Camille)^2 = 49 metres^2 + 49 metres^2 (distance between Eddie and Camille)^2 = 98 metres^2
To find the distance between Eddie and Camille, we take the square root of both sides:
distance between Eddie and Camille = sqrt(98 metres^2) = 9.9 metres
So, Eddie and Camille are approximately 9.9 metres apart, rounded to the nearest tenth.
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