The figure above shows the radiation pattern of an antenna in linear scale.a). If the main lobe magnitude is 4.1, calculate the magnitude of its half power point. b). If the main lobe magnitude is 7 dB, calculate the magnitude of this new half power
Question
The figure above shows the radiation pattern of an antenna in linear scale.a). If the main lobe magnitude is 4.1, calculate the magnitude of its half power point. b). If the main lobe magnitude is 7 dB, calculate the magnitude of this new half power
Solution
a). The half power point of an antenna is typically -3dB down from the peak power. However, in this case, the power is given in linear scale, not in dB. To convert from linear scale to dB, we use the formula dB = 10 * log10(power). So, the main lobe magnitude in dB is 10 * log10(4.1) = 6.12 dB. Now, to find the half power point, we subtract 3 dB from this, giving us 6.12 dB - 3 dB = 3.12 dB. To convert this back to linear scale, we use the formula power = 10^(dB/10), giving us 10^(3.12/10) = 2.08. So, the magnitude of the half power point is 2.08.
b). If the main lobe magnitude is 7 dB, the half power point would be 7 dB - 3 dB = 4 dB.
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