35% of goods were sold at a profit of 65%, while the remaining were sold at x% loss. If the overall loss is 12%, then what is the value of x? (correct to one decimal place)
Question
35% of goods were sold at a profit of 65%, while the remaining were sold at x% loss. If the overall loss is 12%, then what is the value of x? (correct to one decimal place)
Solution
Sure, let's solve this step by step:
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Let's denote the cost price of the goods as C (it doesn't matter what value we choose for C, so we can choose any value that makes the calculation easier. For this problem, let's choose C = 100).
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According to the problem, 35% of the goods were sold at a profit of 65%. So, the selling price for these goods is 135% of C (100% of C + 65% profit).
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The remaining 65% of the goods were sold at a loss of x%. So, the selling price for these goods is (100% - x%) of C.
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The overall selling price is a 12% loss on C, which means it's 88% of C.
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We can now set up the equation: 0.35 * 1.35C + 0.65 * (1 - x/100)C = 0.88C.
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Simplifying the equation gives: 47.25 + 65 - 0.65x = 88.
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Solving for x gives: x = (47.25 + 65 - 88) / 0.65 = 37.31.
So, the value of x is approximately 37.3% (correct to one decimal place).
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