Find the slope of a line perpendicular to the line whose equation is 3, x, plus, 6, y, equals, minus, 543x+6y=−54. Fully simplify your answer
Question
Find the slope of a line perpendicular to the line whose equation is 3, x, plus, 6, y, equals, minus, 543x+6y=−54. Fully simplify your answer
Solution
The equation of the line given is 3x + 6y = -54.
First, we need to find the slope of this line. To do this, we can rearrange the equation into slope-intercept form (y = mx + b), where m is the slope.
Subtract 3x from both sides: 6y = -3x - 54
Then divide every term by 6 to solve for y: y = -1/2x - 9
So, the slope of the given line is -1/2.
The slope of a line perpendicular to a given line is the negative reciprocal of the slope of the given line.
The negative reciprocal of -1/2 is 2.
Therefore, the slope of the line perpendicular to the given line is 2.
Similar Questions
Find the slope of a line parallel to the line whose equation is x, plus, 6, y, equals, minus, 54x+6y=−54. Fully simplify your answer.
Find the slope of a line parallel to the line whose equation is 3, x, plus, 18, y, equals, minus, 4863x+18y=−486. Fully simplify your answer.
Find the slope of a line perpendicular to the line whose equation is 3, x, minus, 3, y, equals, 453x−3y=45. Fully simplify your answer.
What is the slope of the line described by the equation below?y = -6x + 3A.6B.-6C.3D.-3
Find the slope of a line parallel to the line whose equation is 6, x, minus, 10, y, equals, minus, 1006x−10y=−100. Fully simplify your answer
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.