Select the correct answerIn an examination it is required to get 441 of the aggregate marks to pass. A student gets 392 marks and is declared failed by 5% of marks. What are the maximum aggregate marks a student can get?Options98085015001000

To solve this problem, we first need to understand that the student failed by 5% of the total marks. This means that the student needed an additional 5% of the total marks to pass.

The student scored 392 marks but still failed. So, 392 marks is equivalent to 95% (100% - 5% failure) of the total marks.

We can set up the equation:

392 = 0.95 * Total Marks

To find the total marks, we rearrange the equation to solve for Total Marks:

Total Marks = 392 / 0.95

When you calculate the above, you get approximately 412.63. This is the total marks the student needed to pass. However, the question asks for the maximum aggregate marks a student can get.

Since 441 marks is the passing mark, we can set up another equation:

441 = x% * Total Marks

We know that Total Marks is 412.63, so we substitute that into the equation:

441 = x% * 412.63

Solving for x gives us approximately 106.87%. This means that the maximum aggregate marks a student can get is approximately 106.87% of 412.63.

However, the options provided are 980, 850, 1500, and 1000. None of these options match our calculated answer. Therefore, there seems to be a mistake in the question or the provided options.