Use the quadratic formula to solve. Express your answer in simplest form.3, x, squared, plus, 20, x, plus, 25, equals, 03x 2 +20x+25=0

The quadratic formula is used to solve equations of the form ax^2 + bx + c = 0. The formula is:

x = [-b ± sqrt(b^2 - 4ac)] / (2a)

In this case, a = 3, b = 20, and c = 25.

First, calculate the value under the square root, which is b^2 - 4ac:

b^2 - 4ac = (20)^2 - 4325 = 400 - 300 = 100

The square root of 100 is 10.

Then, substitute a, b, and the square root value into the quadratic formula:

x = [-20 ± 10] / (2*3)

This gives two solutions:

x = (-20 + 10) / 6 = -10/6 = -5/3

and

x = (-20 - 10) / 6 = -30/6 = -5

So, the solutions to the equation 3x^2 + 20x + 25 = 0 are x = -5/3 and x = -5.