The value of Ksp for calcium sulfate is 2.4 x 10-5.A solution of calcium sulfate with a concentration of 2.0 x 10-2 mol L-1 is Question 8Select one:a.supersaturated and precipitation of solid calcium sulfate will not occur.b.of unknown saturation so prediction is not possible.c.undersaturated and precipitation of solid calcium sulfate will not occur.d.supersaturated and precipitation of solid calcium sulfate will occur.e.undersaturated and precipitation of solid calcium sulfate will occur.

To answer this question, we first need to understand what Ksp (solubility product constant) is. Ksp is the equilibrium constant for a solid substance dissolving in an aqueous solution. It represents the level at which a solute dissolves in solution. The smaller the Ksp, the less soluble the compound.

The solubility product of calcium sulfate (CaSO4) is given as 2.4 x 10^-5. This value is an equilibrium constant, which means it is the product of the concentrations of the ions in the solution when the solution is saturated.

The given concentration of the calcium sulfate solution is 2.0 x 10^-2 mol L^-1.

To find out if the solution is saturated, undersaturated, or supersaturated, we need to compare the given concentration with the Ksp.

If the ion product (concentration of Ca2+ times concentration of SO4^2-) is equal to Ksp, the solution is saturated. If the ion product is less than Ksp, the solution is undersaturated. If the ion product is greater than Ksp, the solution is supersaturated.

In the case of CaSO4, it dissociates into Ca2+ and SO4^2-, each with a concentration of 2.0 x 10^-2 mol L^-1. So, the ion product is (2.0 x 10^-2) * (2.0 x 10^-2) = 4.0 x 10^-4.

Since 4.0 x 10^-4 is greater than the Ksp (2.4 x 10^-5), the solution is supersaturated.

Therefore, the correct answer is:

d. supersaturated and precipitation of solid calcium sulfate will occur.