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A spinning ice-skater demonstrates of angular momentum. When he pulls in his arms, he spins faster. Without an external , his angular momentum does not change and L = Iω is . The increased angular velocity must be accompanied by a decreased moment of inertia.

Question

A spinning ice-skater demonstrates of angular momentum. When he pulls in his arms, he spins faster. Without an external , his angular momentum does not change and L = Iω is . The increased angular velocity must be accompanied by a decreased moment of inertia.

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Solution

The text you provided is a description of the principle of conservation of angular momentum. Here's a step-by-step explanation:

  1. An ice-skater spinning on ice is an example of a body in rotation, and thus has angular momentum. Angular momentum (L) is the rotational equivalent of linear momentum and is given by the product of the moment of inertia (I) and the angular velocity (ω).

  2. When the ice-skater pulls in his arms, he is reducing his moment of inertia. The moment of inertia is a measure of an object's resistance to changes in rotation rate. It depends on both the mass of the object and its distribution of mass around the axis of rotation. By pulling his arms in, the skater is changing the distribution of his mass so that more of it is closer to his axis of rotation, thus reducing his moment of inertia.

  3. According to the conservation of angular momentum, if no external torque (rotational force) is acting on the system, the total angular momentum of the system remains constant. In this case, the ice-skater and his arms form a closed system, and there is no external torque acting on it.

  4. Therefore, when the skater pulls in his arms and reduces his moment of inertia (I), his angular velocity (ω) must increase in order for the product Iω (which equals the angular momentum L) to remain constant.

  5. This is why the skater spins faster when he pulls in his arms: it's a consequence of the conservation of angular momentum.

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