A train accelerates from rest at a constant rate 𝛼 for distance x1 and time t1. After that it retards to rest at constant rate 𝛽 for distance x2 and time t2. Which of the following relations is correct?A 𝑥1𝑥2=𝛼𝛽=𝑡1𝑡2B 𝑥1𝑥2=𝛽𝛼=𝑡1𝑡2C 𝑥1𝑥2=𝛼𝛽=𝑡2𝑡1D
Question
A train accelerates from rest at a constant rate 𝛼 for distance x1 and time t1. After that it retards to rest at constant rate 𝛽 for distance x2 and time t2. Which of the following relations is correct?A 𝑥1𝑥2=𝛼𝛽=𝑡1𝑡2B 𝑥1𝑥2=𝛽𝛼=𝑡1𝑡2C 𝑥1𝑥2=𝛼𝛽=𝑡2𝑡1D
Solution
First, let's consider the first part of the journey where the train accelerates from rest at a constant rate 𝛼 for distance x1 and time t1.
Using the equation of motion: s = ut + 0.5at^2 where: s = distance u = initial velocity a = acceleration t = time
Since the train starts from rest, u = 0. So, the equation becomes: x1 = 0.5𝛼t1^2
Next, let's consider the second part of the journey where the train retards to rest at constant rate 𝛽 for distance x2 and time t2.
Again using the equation of motion, and since the train finally comes to rest, the equation becomes: x2 = 0.5𝛽t2^2
Now, let's divide the first equation by the second equation:
(x1/x2) = (0.5𝛼t1^2) / (0.5𝛽t2^2) => (x1/x2) = (𝛼/𝛽) * (t1/t2)^2
So, the correct relation is not given in the options A, B, C, or D. The correct relation should be (x1/x2) = (𝛼/𝛽) * (t1/t2)^2.
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