Select the correct answerThere are two water tanks A and B. A is much smaller than B. While water fills at the rate of one litre every hour in A, it gets filled up like 10, 20, 40, 80, 160….., in tank B. (At the end of first hour, B has 10 liters, second hour it has 20, and so on). If tank B is 1/16 filled after 17 hours, what is the total duration required to fill it completely?radio_button_unchecked4 hoursradio_button_unchecked21 hoursradio_button_unchecked22 hoursradio_button_unchecked24 hours
Question
Select the correct answerThere are two water tanks A and B. A is much smaller than B. While water fills at the rate of one litre every hour in A, it gets filled up like 10, 20, 40, 80, 160….., in tank B. (At the end of first hour, B has 10 liters, second hour it has 20, and so on). If tank B is 1/16 filled after 17 hours, what is the total duration required to fill it completely?radio_button_unchecked4 hoursradio_button_unchecked21 hoursradio_button_unchecked22 hoursradio_button_unchecked24 hours
Solution
The water in tank B fills up in a geometric progression - 10, 20, 40, 80, 160 and so on. This is a doubling sequence.
After 17 hours, tank B is 1/16 filled. This means that the tank will be completely filled in 4 more doublings (since 2^4 = 16).
Therefore, the total duration required to fill the tank completely is 17 hours (already passed) + 4 hours (for the remaining doublings) = 21 hours.
So, the correct answer is 21 hours.
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