What will be the output of the following pseudo code a=3, b=7, c=10?1. 2. Integer funn (Interger a, Integer b, Integer c)3. c=(c&3)+c4. b=b&c5. a=(2+4)+a6. return a+b+c

The pseudo code provided seems to be a mix of different programming languages. However, it appears to be closest to Java or C++. Here's a step-by-step breakdown of what the code does:

1. The function funn is defined, which takes three integers a, b, and c as parameters. In this case, a is 3, b is 7, and c is 10.

2. In the line c=(c&3)+c, the bitwise AND operation is performed between c (which is 10 in binary form 1010) and 3 (which is 11 in binary). The result is 2 (which is 10 in binary). This is then added to c, so c becomes 12.

3. In the line b=b&c, the bitwise AND operation is performed between b (which is 7 in binary form 0111) and c (which is 12 in binary form 1100). The result is 4, so b becomes 4.

4. In the line a=(2+4)+a, 2 and 4 are added together to get 6, and then this is added to a (which is 3), so a becomes 9.

5. Finally, a, b, and c are added together and returned by the function. So, 9 (value of a) + 4 (value of b) + 12 (value of c) = 25.

So, the output of the pseudo code will be 25.

The pseudo code provided seems to be a mix of different programming languages. However, it appears to be closest to Java or C++. Here's a step-by-step breakdown of what the code does:

1. The function funn is defined, which takes three integers a, b, and c as parameters. In this case, a is 3, b is 7, and c is 10.

2. In line 3, c is updated. The expression (c&3) performs a bitwise AND operation between c (which is 10 in binary form 1010) and 3 (which is 11 in binary). The result is 2 (which is 10 in binary). This is then added to the original c, so c becomes 12.

3. In line 4, b is updated. The expression b&c performs a bitwise AND operation between b (which is 7 in binary form 0111) and c (which is now 12 in binary form 1100). The result is 4, so b becomes 4.

4. In line 5, a is updated. The expression (2+4)+a simply adds 6 to the original a, so a becomes 9.

5. Finally, in line 6, the function returns the sum of a, b, and c, which is 9 + 4 + 12 = 25.

So, the output of the pseudo code will be 25.