moment of inertia of a semi circular disc
Question
moment of inertia of a semi circular disc
Solution
The moment of inertia of a semi-circular disc about an axis perpendicular to the plane of the disc and passing through its center can be calculated using the formula for the moment of inertia of a full disc and then dividing by 2, since a semi-circular disc is half of a full disc.
Here are the steps:
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The moment of inertia (I) of a full disc is given by the formula I = 1/2 * m * r^2, where m is the mass of the disc and r is the radius.
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Since a semi-circular disc is half of a full disc, its moment of inertia would be half of the moment of inertia of a full disc. Therefore, the moment of inertia of a semi-circular disc is given by I = 1/2 * (1/2 * m * r^2).
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Simplifying the above expression gives I = 1/4 * m * r^2.
So, the moment of inertia of a semi-circular disc about an axis perpendicular to the plane of the disc and passing through its center is 1/4 * m * r^2.
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