The output of the Python code `print('{0:.4}'.format(1/9))` will be `0.1111`.

Here's the step by step explanation:

1. The `format()` function is a built-in Python function that formats specified values and inserts them inside the string's placeholder. The placeholder is defined using curly brackets `{}`.

2. Inside the placeholder, you can define the formatting. In this case, `0:.4` is used. The `0` refers to the argument that you want to format (in this case, the result of `1/9`), and `.4` specifies the precision of the number - that is, the number of digits after the decimal point.

3. `1/9` results in `0.1111111111111111`. But because of the `.4` precision specifier, only the first four digits after the decimal point are printed.

So, the output will be `0.1111`.

Question

The output of the Python code `print('{0:.4}'.format(1/9))` will be `0.1111`.

Here's the step by step explanation:

1. The `format()` function is a built-in Python function that formats specified values and inserts them inside the string's placeholder. The placeholder is defined using curly brackets `{}`.

2. Inside the placeholder, you can define the formatting. In this case, `0:.4` is used. The `0` refers to the argument that you want to format (in this case, the result of `1/9`), and `.4` specifies the precision of the number - that is, the number of digits after the decimal point.

3. `1/9` results in `0.1111111111111111`. But because of the `.4` precision specifier, only the first four digits after the decimal point are printed.

So, the output will be `0.1111`.

Knowee AI · Accepted Answer

The output of the Python code `print('{0:.4}'.format(1/9))` will be `0.1111`.

Here's the step by step explanation:

1. The `format()` function is a built-in Python function that formats specified values and inserts them inside the string's placeholder. The placeholder is defined using curly brackets `{}`.

2. Inside the placeholder, you can define the formatting. In this case, `0:.4` is used. The `0` refers to the argument that you want to format (in this case, the result of `1/9`), and `.4` specifies the precision of the number - that is, the number of digits after the decimal point.

3. `1/9` results in `0.1111111111111111`. But because of the `.4` precision specifier, only the first four digits after the decimal point are printed.

So, the output will be `0.1111`.

What will be the output of the following Python code?print('{0:.4}'.format(1/9))Options0.11110.1111:.4Error11.11%

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