The correct reagents to convert acetone into isopropylamine are [H+], NH3, NaBH3CN.

Here's the step-by-step process:

1) The first step is the formation of an imine. This is done by reacting acetone with NH3 in the presence of a catalytic amount of acid [H+]. The acid protonates the oxygen of the carbonyl group in acetone, making it more electrophilic and susceptible to nucleophilic attack by NH3. The water molecule is then eliminated to form an imine.

2) The second step is the reduction of the imine to an amine. This is done by reacting the imine with NaBH3CN. The NaBH3CN acts as a reducing agent, donating a hydride ion (H-) to the imine, converting it into an amine.

So, the correct answer is [H+], NH3, NaBH3CN.

Question

The correct reagents to convert acetone into isopropylamine are [H+], NH3, NaBH3CN.

Here's the step-by-step process:

1) The first step is the formation of an imine. This is done by reacting acetone with NH3 in the presence of a catalytic amount of acid [H+]. The acid protonates the oxygen of the carbonyl group in acetone, making it more electrophilic and susceptible to nucleophilic attack by NH3. The water molecule is then eliminated to form an imine.

2) The second step is the reduction of the imine to an amine. This is done by reacting the imine with NaBH3CN. The NaBH3CN acts as a reducing agent, donating a hydride ion (H-) to the imine, converting it into an amine.

So, the correct answer is [H+], NH3, NaBH3CN.

Knowee AI · Accepted Answer

The correct reagents to convert acetone into isopropylamine are [H+], NH3, NaBH3CN.

Here's the step-by-step process:

1) The first step is the formation of an imine. This is done by reacting acetone with NH3 in the presence of a catalytic amount of acid [H+]. The acid protonates the oxygen of the carbonyl group in acetone, making it more electrophilic and susceptible to nucleophilic attack by NH3. The water molecule is then eliminated to form an imine.

2) The second step is the reduction of the imine to an amine. This is done by reacting the imine with NaBH3CN. The NaBH3CN acts as a reducing agent, donating a hydride ion (H-) to the imine, converting it into an amine.

So, the correct answer is [H+], NH3, NaBH3CN.

Identify reagents that can be used to convert acetone into isopropylamine.Select answer from the options below[H+], NH31) LiAlH4 2) NaNH2[H+], NH3, NaBH3CN[H+], NH3, NaBH4

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