What is the probability of throwing a total of 8 or 11 in a single throw of a pair of dice?

To calculate the probability of throwing a total of 8 or 11 in a single throw of a pair of dice, we first need to know the total number of possible outcomes. When throwing two dice, there are 6 possible outcomes for each die, so the total number of outcomes is 6*6 = 36.

Next, we need to calculate the number of outcomes that result in a total of 8 or 11. The combinations that give a total of 8 are: (2,6), (3,5), (4,4), (5,3), (6,2). So there are 5 combinations for each die, giving a total of 5*2 = 10 outcomes.

The combinations that give a total of 11 are: (5,6), (6,5). So there are 2 combinations for each die, giving a total of 2*2 = 4 outcomes.

So the total number of outcomes that result in a total of 8 or 11 is 10 + 4 = 14.

The probability of throwing a total of 8 or 11 is therefore 14/36 = 0.3889, or approximately 38.89%.