Select the correct answerWhat will be the output of the given code snippet?#include <stdio.h>int Function(char *S) {  if (S == NULL || *S ==' ') return 0;  int C = 1, i = 1;  while (*(S+C)) {    if (S[C] != S[C-1]) {      S[i] = S[C];      i++;    }    C++;  }  *(S+i)=' ';  return i;} int main() {  char S[] = "codetantraC";  Function(S);  puts(S);  return 0;}OptionsCompile Time ErrorPrints "CodetantraC"Prints "codetantraC"Runtime ErrorPrints "codetantrac"Prints "Codetantrac"

The correct answer is "Prints "codetantraC"".

Here's the step by step explanation:

1. The main function calls the Function with the string "codetantraC".
2. The Function checks if the string is NULL or if the first character is a space. If either of these conditions is true, it returns 0. In this case, neither is true, so it continues.
3. It initializes two counters, C and i, to 1.
4. It enters a while loop that continues as long as the character at the Cth position in the string is not the null character.
5. Inside the loop, it checks if the character at the Cth position is different from the character at the (C-1)th position. If it is, it copies the character at the Cth position to the ith position and increments i.
6. It increments C and repeats the loop.
7. After the loop, it sets the character at the ith position to a space and returns i.
8. Back in the main function, it calls puts with the modified string, which prints "codetantraC" to the console.