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elect the correct answerThe efficiency of Rohil is twice that of Sanjay and he can finish a work in 4h less than the time taken by Sanjay. If both of them work together they can finish the same work?Options3h8h8/3h4/3h

Question

elect the correct answerThe efficiency of Rohil is twice that of Sanjay and he can finish a work in 4h less than the time taken by Sanjay. If both of them work together they can finish the same work?Options3h8h8/3h4/3h

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Solution

Let's solve this step by step:

  1. Let's assume the time taken by Sanjay to finish the work alone is 'x' hours.

  2. Since Rohil is twice as efficient as Sanjay, he would take half the time taken by Sanjay to finish the work. So, Rohil takes 'x/2' hours to finish the work.

  3. According to the problem, Rohil takes 4 hours less than Sanjay to finish the work. So, 'x/2 = x - 4'. Solving this equation, we get 'x = 8'. So, Sanjay takes 8 hours to finish the work alone.

  4. Rohil, being twice as efficient, takes half the time, which is 4 hours.

  5. If they work together, their combined rate is the sum of their individual rates. The rate of Sanjay is 1 job per 8 hours (1/8 job/hour) and the rate of Rohil is 1 job per 4 hours (1/4 job/hour).

  6. So, their combined rate is 1/8 + 1/4 = 3/8 job/hour.

  7. Therefore, to complete 1 job, they would take 1 / (3/8) = 8/3 hours.

So, the correct answer is 8/3 hours.

This problem has been solved

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