To reverse the first half and second half of the array, we can follow these steps: 1. Read the size of the array (N) from the input. 2. Read the array elements from the input and store them in an array. 3. Calculate the midpoint of the array by dividing the size (N) by 2. 4. Iterate from index 0 to the midpoint - 1 and swap each element with its corresponding element from the second half of the array. 5. Print the reversed array. Here is the code in C to implement the above steps: ```c #include int main() { int N; scanf("%d", &N); int arr[N]; for (int i = 0; i

Question

To reverse the first half and second half of the array, we can follow these steps:

1. Read the size of the array (N) from the input.
2. Read the array elements from the input and store them in an array.
3. Calculate the midpoint of the array by dividing the size (N) by 2.
4. Iterate from index 0 to the midpoint - 1 and swap each element with its corresponding element from the second half of the array.
5. Print the reversed array.

Here is the code in C to implement the above steps:

```c
#include <stdio.h>

int main() {
    int N;
    scanf("%d", &N);

int arr[N];
    for (int i = 0; i < N; i++) {
        scanf("%d", &arr[i]);
    }

int midpoint = N / 2;
    for (int i = 0; i < midpoint; i++) {
        int temp = arr[i];
        arr[i] = arr[N - i - 1];
        arr[N - i - 1] = temp;
    }

for (int i = 0; i < N; i++) {
        printf("%d ", arr[i]);
    }

return 0;
}
```

This code reads the size of the array, reads the array elements, reverses the first half and second half of the array, and then prints the reversed array.

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