Consider two identical waves (both with a wavelength of 55 m) emitted in phase arriving at a point from two sources such that one of the waves has travelled 1515 m more than the other. How do the two waves combine at this point?A. Perfectly ConstructivelyB. Perfectly DestructivelyC. Partially constructively/destructively

To answer this question, we need to understand the concept of wave interference, which is the phenomenon that occurs when two waves meet while traveling along the same medium.

The key point here is the difference in the distances travelled by the two waves, which is 1515 m. We need to find out how many wavelengths this distance corresponds to.

The wavelength of the waves is given as 55 m. So, we divide the difference in the distances by the wavelength to find out how many wavelengths fit into this distance:

1515 m / 55 m/wavelength = 27.55 wavelengths

This is very close to 28, which is an integer number, meaning that the waves have travelled a whole number of wavelengths apart.

When the path difference is a whole number of wavelengths, the waves arrive in phase - the peaks align with the peaks and the troughs align with the troughs. This is known as constructive interference, so the waves combine perfectly constructively at this point.

So, the answer is A. Perfectly Constructively.