Solve the equation 5q2+36q+7=0.

This is a quadratic equation of the form ax^2 + bx + c = 0. We can solve it using the quadratic formula, which is x = [-b ± sqrt(b^2 - 4ac)] / (2a).

Here, a = 5, b = 36, and c = 7.

Step 1: Calculate the discriminant, which is b^2 - 4ac. Discriminant = (36)^2 - 457 = 1296 - 140 = 1156

Step 2: Substitute a, b, and the discriminant into the quadratic formula to find the solutions.

q = [-36 ± sqrt(1156)] / (2*5)

So, the solutions are:

q1 = [-36 + sqrt(1156)] / 10 = -0.19 q2 = [-36 - sqrt(1156)] / 10 = -7.31

So, the solutions to the equation 5q^2 + 36q + 7 = 0 are q = -0.19 and q = -7.31.