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You're developing a Bash script that reads lines from a text file. If a line contains the word "error," the script should display an error message and continue reading the next line. If a line contains the word "success," it should display a success message and break out of the loop. For all other lines, it should display a generic message. Which code snippet correctly implements this behavior using a while loop?1.0 Markswhile read -r line; doif [[ "$line" == *"error"* ]]; thenecho "Error: $line"elif [[ "$line" == *"success"* ]]; thenecho "Success: $line"breakelseecho "Info: $line"fidone < file.txtwhile IFS= read -r line; doif [[ "$line" =~ "error" ]]; thenecho "Error: $line"elif [[ "$line" =~ "success" ]]; thenecho "Success: $line"breakelseecho "Info: $line"fidone < file.txtwhile read -r line; doif [[ "$line" =~ "error" ]]; thenecho "Error: $line"elif [[ "$line" =~ "success" ]]; thenecho "Success: $line"breakelseecho "Info: $line"fidone < file.txtwhile IFS= read -r line; doif [[ "$line" == *error* ]]; thenecho "Error: $line"elif [[ "$line" == *success* ]]; thenecho "Success: $line"breakelseecho "Info: $line"fidone < file.txtPowered by Fedena

Question

You're developing a Bash script that reads lines from a text file. If a line contains the word "error," the script should display an error message and continue reading the next line. If a line contains the word "success," it should display a success message and break out of the loop. For all other lines, it should display a generic message. Which code snippet correctly implements this behavior using a while loop?1.0 Markswhile read -r line; doif [[ "line"=="error"]];thenecho"Error:line" == *"error"* ]]; thenecho "Error: line"elif [[ "line"=="success"]];thenecho"Success:line" == *"success"* ]]; thenecho "Success: line"breakelseecho "Info: line"fidone<file.txtwhileIFS=readrline;doif[["line"fidone < file.txtwhile IFS= read -r line; doif [[ "line" =~ "error" ]]; thenecho "Error: line"elif[["line"elif [[ "line" =~ "success" ]]; thenecho "Success: line"breakelseecho"Info:line"breakelseecho "Info: line"fidone < file.txtwhile read -r line; doif [[ "line"= "error"]];thenecho"Error:line" =~ "error" ]]; thenecho "Error: line"elif [[ "line"= "success"]];thenecho"Success:line" =~ "success" ]]; thenecho "Success: line"breakelseecho "Info: line"fidone<file.txtwhileIFS=readrline;doif[["line"fidone < file.txtwhile IFS= read -r line; doif [[ "line" == error ]]; thenecho "Error: line"elif[["line"elif [[ "line" == success ]]; thenecho "Success: line"breakelseecho"Info:line"breakelseecho "Info: line"fidone < file.txtPowered by Fedena

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Solution

The correct code snippet that implements the desired behavior using a while loop in Bash is:

while IFS= read -r line; do
  if [[ "$line" =~ "error" ]]; then
    echo "Error: $line"
  elif [[ "$line" =~ "success" ]]; then
    echo "Success: $line"
    break
  else
    echo "Info: $line"
  fi
done < file.txt

This script reads lines from a file. If a line contains the word "error", it displays an error message. If a line contains the word "success", it displays a success message and breaks out of the loop. For all other lines, it displays a generic message. The IFS= before read -r line ensures that leading and trailing whitespaces in the line are preserved. The =~ operator in the if and elif conditions is used for pattern matching in Bash.

This problem has been solved

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