State and prove symmetry property of DTFT.
Question
State and prove symmetry property of DTFT.
Solution
The Symmetry Property of the Discrete Time Fourier Transform (DTFT) states that if x[n] is a sequence, then its DTFT X(e^jω) and the DTFT of its complex conjugate x*[n] are related as follows:
X(e^-jω) = X*(e^jω)
Proof:
Let's start with the definition of the DTFT:
X(e^jω) = Σ x[n] e^-jωn
where the sum is over all n.
Now, let's consider the complex conjugate of X(e^jω):
X*(e^jω) = Σ x*[n] e^jωn
where again the sum is over all n.
Now, let's replace e^jω with e^-j(-ω):
X*(e^jω) = Σ x*[n] e^-j(-ω)n
This is exactly the definition of the DTFT of x*[n] evaluated at -ω. Therefore, we have shown that:
X(e^-jω) = X*(e^jω)
This completes the proof of the symmetry property of the DTFT.
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