A group of people estimate the number of Blue m&m's in a large jar. They each take a sample of 20 m&m's and count the number of blue m&m's before returning them to the jar. Here is the data from the samples:Number of Blue m&m's Number of Samples4 25 56 97 78 39 110 211 1What percent of samples had more than 9 blue m&m's? Round to the nearest tenth of a percent.
Question
A group of people estimate the number of Blue m&m's in a large jar. They each take a sample of 20 m&m's and count the number of blue m&m's before returning them to the jar. Here is the data from the samples:Number of Blue m&m's Number of Samples4 25 56 97 78 39 110 211 1What percent of samples had more than 9 blue m&m's? Round to the nearest tenth of a percent.
Solution 1
To answer this question, we first need to determine the total number of samples and the number of samples that had more than 9 blue M&M's.
From the data, we can see that the total number of samples is the sum of the number of samples for each number of blue M&M's. This is calculated as follows:
25 (for 4 blue M&M's) + 5 (for 5 blue M&M's) + 9 (for 6 blue M&M's) + 7 (for 7 blue M&M's) + 3 (for 8 blue M&M's) + 1 (for 9 blue M&M's) + 2 (for 10 blue M&M's) + 1 (for 11 blue M&M's) = 53 samples in total.
The number of samples that had more than 9 blue M&M's is the sum of the number of samples for 10 and 11 blue M&M's, which is 2 + 1 = 3.
To find the percentage of samples that had more than 9 blue M&M's, we divide the number of samples with more than 9 blue M&M's by the total number of samples and multiply by 100. This is calculated as follows:
(3 / 53) * 100 = 5.66%.
Rounding to the nearest tenth of a percent, we get 5.7%. So, 5.7% of samples had more than 9 blue M&M's.
Solution 2
To answer this question, we first need to determine the total number of samples and the number of samples that had more than 9 blue M&M's.
From the data, we can see that the total number of samples is the sum of the number of samples for each number of blue M&M's. This is calculated as follows:
25 (for 4 blue M&M's) + 5 (for 5 blue M&M's) + 9 (for 6 blue M&M's) + 7 (for 7 blue M&M's) + 3 (for 8 blue M&M's) + 1 (for 9 blue M&M's) + 2 (for 10 blue M&M's) + 1 (for 11 blue M&M's) = 53 samples in total.
The number of samples that had more than 9 blue M&M's is the sum of the number of samples for 10 and 11 blue M&M's, which is 2 + 1 = 3.
To find the percentage of samples that had more than 9 blue M&M's, we divide the number of samples with more than 9 blue M&M's by the total number of samples and multiply by 100. This is calculated as follows:
(3 / 53) * 100 = 5.66...%
Rounding to the nearest tenth of a percent, we get 5.7%. So, 5.7% of samples had more than 9 blue M&M's.
Solution 3
To find the percentage of samples that had more than 9 blue M&M's, we first need to determine the total number of samples and the number of samples that had more than 9 blue M&M's.
From the data, we can see that the total number of samples is the sum of the number of samples for each number of blue M&M's. This is calculated as follows:
25 (for 4 blue M&M's) + 5 (for 5 blue M&M's) + 9 (for 6 blue M&M's) + 7 (for 7 blue M&M's) + 3 (for 8 blue M&M's) + 1 (for 9 blue M&M's) + 2 (for 10 blue M&M's) + 1 (for 11 blue M&M's) = 53 samples in total.
The number of samples that had more than 9 blue M&M's is the sum of the number of samples for 10 and 11 blue M&M's, which is 2 + 1 = 3.
To find the percentage, we divide the number of samples with more than 9 blue M&M's by the total number of samples and multiply by 100:
(3 / 53) * 100 = 5.66...%
Rounding to the nearest tenth of a percent, we get 5.7%. So, 5.7% of samples had more than 9 blue M&M's.
Solution 4
To find the percentage of samples that had more than 9 blue M&M's, we first need to determine the total number of samples and the number of samples that had more than 9 blue M&M's.
From the data, we can see that the total number of samples is the sum of the number of samples for each number of blue M&M's. This is calculated as follows:
25 (for 4 blue M&M's) + 5 (for 5 blue M&M's) + 9 (for 6 blue M&M's) + 7 (for 7 blue M&M's) + 3 (for 8 blue M&M's) + 1 (for 9 blue M&M's) + 2 (for 10 blue M&M's) + 1 (for 11 blue M&M's) = 53 samples in total.
The number of samples that had more than 9 blue M&M's is the sum of the number of samples for 10 and 11 blue M&M's, which is 2 + 1 = 3.
To find the percentage, we divide the number of samples with more than 9 blue M&M's by the total number of samples and multiply by 100:
(3 / 53) * 100 = 5.66...%
Rounding to the nearest tenth of a percent, we get 5.7%. So, 5.7% of samples had more than 9 blue M&M's.
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