A sample of helium gas has a volume of 1.60L at 345.K and 30.5atm. When the gas changes to 0.600L at 315.K, what is the final pressure? Round your answer to 3 significant figures.
Question
A sample of helium gas has a volume of 1.60L at 345.K and 30.5atm. When the gas changes to 0.600L at 315.K, what is the final pressure? Round your answer to 3 significant figures.
Solution
To solve this problem, we can use the combined gas law which states that the ratio of the product of pressure and volume to temperature of one state is equal to the ratio of the product of pressure and volume to temperature of another state. The formula is (P1V1)/T1 = (P2V2)/T2.
Given: P1 = 30.5 atm V1 = 1.60 L T1 = 345 K V2 = 0.600 L T2 = 315 K P2 = ?
We are solving for P2, so rearrange the formula to solve for P2: P2 = (P1V1T2) / (T1*V2)
Substitute the given values into the formula: P2 = (30.5 atm * 1.60 L * 315 K) / (345 K * 0.600 L)
Perform the calculation to find P2.
After performing the calculation, round your answer to three significant figures.
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