Dhar bought two articles A and B at a total cost of8000. He sold article A at 20% profit and articleB at 12% loss. In the whole deal, he made no gainand no loss. At what price should Dhar have soldarticle B to make an overall profit of 25%?[RBI Gr. 'B' (Phase I) Exam, 2015](a) 5200(b) 5800(c) * 6400(d) * 6200​

Let's solve this step by step:

Step 1: Let's assume the cost price of article A as 'a' and article B as 'b'. So, a + b = 8000 (Given total cost of both articles is 8000)

Step 2: According to the problem, Dhar sold article A at 20% profit and article B at 12% loss, but overall he made no profit no loss. So, the selling price of A and B together is also 8000.

We can write this as: a120/100 + b88/100 = 8000

Step 3: Now we have two equations, and we can solve them to find the values of 'a' and 'b'.

From step 1, we can express 'a' as 8000 - b. Substituting this in the equation from step 2, we get:

(8000 - b)120/100 + b88/100 = 8000

Solving this equation, we get b = 4000. Substituting b = 4000 in the equation a + b = 8000, we get a = 4000.

Step 4: Now, to make an overall profit of 25%, Dhar should have sold both articles for a total of 8000*125/100 = 10000.

Step 5: He sold article A at 20% profit, which is 4000*120/100 = 4800.

So, to achieve a total selling price of 10000, he should have sold article B for 10000 - 4800 = 5200.

So, the answer is (a) 5200.