Select the correct answerPredict the output of the given code snippet#include<stdio.h>void Function(int s, ...) { printf("%d ", s);} int main() { Function(1, 2, 3, 4); Function(5, 6, 7); Function(8, 9); return 0;}Options1 2 3 4 5 6 7 8 91 5 84 7 9Error
Question
Select the correct answerPredict the output of the given code snippet#include<stdio.h>void Function(int s, ...) { printf("%d ", s);} int main() { Function(1, 2, 3, 4); Function(5, 6, 7); Function(8, 9); return 0;}Options1 2 3 4 5 6 7 8 91 5 84 7 9Error
Solution
The correct answer is "1 5 8".
The reason is that the function "Function" only takes one argument and prints it. The other arguments (2, 3, 4, 6, 7, 9) are ignored because they are not used in the function. So, when you call Function(1, 2, 3, 4), it only prints "1". Similarly, Function(5, 6, 7) prints "5" and Function(8, 9) prints "8". Hence, the output is "1 5 8".
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