To allocate enough space for an array of 10 integers (on a 64bit, Linux machine), I can use:malloc(64 * 10)malloc(10 * int)malloc(10 * sizeof(int))
Question
To allocate enough space for an array of 10 integers (on a 64bit, Linux machine), I can use:malloc(64 * 10)malloc(10 * int)malloc(10 * sizeof(int))
Solution
The correct way to allocate enough space for an array of 10 integers on a 64-bit Linux machine is to use malloc(10 * sizeof(int)).
Here's why:
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malloc(64 * 10)is incorrect because it allocates 640 bytes. This might be more than you need, or it might not be enough, depending on the size of an integer on your system. On a 64-bit system, an integer is typically 4 bytes, so you would only need 40 bytes to store 10 integers. -
malloc(10 * int)is incorrect becauseintis a type, not a value. You can't multiply by a type in C. -
malloc(10 * sizeof(int))is correct. Thesizeofoperator gives you the size of a type in bytes. On a 64-bit Linux system,sizeof(int)is typically 4, so10 * sizeof(int)gives you exactly the 40 bytes you need to store 10 integers.
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