For the vessel containing glycerin under pressure as shown in Fig. 2-2, find the pressure at the bottom of the tank.QUESTION 1ANSWERA.99.45 kPaB.74.68 kPaC.85.63 kPaD.52.11 kPa
Question
For the vessel containing glycerin under pressure as shown in Fig. 2-2, find the pressure at the bottom of the tank.QUESTION 1ANSWERA.99.45 kPaB.74.68 kPaC.85.63 kPaD.52.11 kPa
Solution
To find the pressure at the bottom of the tank, we can use the hydrostatic pressure formula. The formula states that the pressure at a certain depth in a fluid is equal to the product of the density of the fluid, the acceleration due to gravity, and the depth.
In this case, the glycerin is under pressure, so we need to consider the pressure due to the weight of the glycerin above the bottom of the tank.
First, we need to determine the depth of the glycerin. Looking at Fig. 2-2, we can see that the depth is given as 1.5 meters.
Next, we need to know the density of glycerin. The density of glycerin is typically around 1.26 g/cm^3 or 1260 kg/m^3.
We also need to know the acceleration due to gravity, which is approximately 9.8 m/s^2.
Now we can calculate the pressure at the bottom of the tank using the formula:
Pressure = density * gravity * depth
Plugging in the values, we get:
Pressure = 1260 kg/m^3 * 9.8 m/s^2 * 1.5 m
Calculating this, we find:
Pressure = 18,522 N/m^2
Converting this to kilopascals (kPa), we divide by 1000:
Pressure = 18.522 kPa
Therefore, the pressure at the bottom of the tank is approximately 18.522 kPa.
None of the given answer choices match the calculated pressure, so none of the options A, B, C, or D are correct.
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