A particle undergoes simple harmonic motion having time-period T. The time taken 3/8th oscillation is-
Question
A particle undergoes simple harmonic motion having time-period T. The time taken 3/8th oscillation is-
Solution
The time period T is the time it takes for one complete cycle of oscillation.
If we want to find the time taken for 3/8th of an oscillation, we simply need to multiply the time period T by 3/8.
So, the time taken for 3/8th of an oscillation is (3/8)T.
Similar Questions
A particle executes simple harmonic oscillation with an amplitude A𝐴. The period of oscillation is T𝑇. The minimum time taken by the particle to travel half of the amplitude from the equilibrium position is
A body is vibrating in simple harmonic motion. If its acceleration is 12 cm s−212 cm s-2 at a displacement 3 cm,3 cm, then time period isA6.28 s
A particle undergoes simple harmonic motion of amplitude x0 and frequency f . What is theaverage speed of the particle during one oscillation?
A particle executes simple harmonicmotion with an amplitude of 5 cm.When the particle is at 4 cm from themean position, the magnitude of itsvelocity in SI units is equal to that of itsacceleration. Then, its periodic time inseconds is
The equation of displacement of a harmonic oscillator is x=3sinωt+4cosωt. The amplitude of the particles will be
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.